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下面一段c++,opencv代码- void ThinImage(IplImage* src, IplImage* dst, int iterations)
- {
- CvSize size = cvGetSize(src);
- cvCopy(src, dst);//拷贝一个数组给另一个数组
- int n = 0,i = 0,j = 0;
- for(n=0; n<iterations; n++)
- {
- IplImage* t_image;
-
- t_image = cvCloneImage(dst);
- for(i=0; i<size.height; i++)
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我在c#中emgucv代码- void ThinImage(IntPtr src, IntPtr dst, int iterations)
- {
- Size size = CvInvoke.cvGetSize(src);
- CvInvoke.cvCopy(src, dst, IntPtr.Zero);
- int n = 0, i = 0, j = 0;
- for (n= 0; n < iterations; n++)
- {
- IntPtr t_image;
- t_image=Emgu.CV.CvInvoke[color=#FF0000].?????[/color]
- }
- }
复制代码 ?号部分没有cvcloneimage这个方法???求大神们不吝赐教啊! |
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